Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/3/83 based; site hou2g.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxb!mhuxn!mhuxm!mhuxj!houxm!hou2g!vdb From: vdb@hou2g.UUCP (R.VANDERBEI) Newsgroups: net.math Subject: uniform continuity Message-ID: <393@hou2g.UUCP> Date: Sun, 27-Jan-85 13:13:42 EST Article-I.D.: hou2g.393 Posted: Sun Jan 27 13:13:42 1985 Date-Received: Mon, 28-Jan-85 06:07:36 EST Organization: AT&T Bell Labs, Holmdel NJ Lines: 28 The usual definition of uniform continuity goes as follows: for every epsilon > 0, there exists a delta > 0 such that |f(x) - f(y)| < epsilon whenever |x - y| < delta. It is not hard (and so I leave it to you readers) to show that the following condition is equivalent: for every epsilon > 0, there exists a K < infinity such that for all x and y, |f(x) - f(y)| < K |x - y| + epsilon. This second formulation shows that uniform continuity is almost the same as Lipschitz continuity (which corresponds to being able to find a finite K even when epsilon is zero). If you think about it (and especially, if you write down a proof), you will see that the first condition is like a "differential" statement and the second condition is like an "integral" version. The reason I was interested in this is because I wanted to know whether a uniformly continuous function could grow more rapidly than linearly at infinity. The second condition shows that it cannot. The second condition appears so simple and ellegant (and the proof is also straight forward) that you'd expect to be able to find it in any textbook on analysis however I have not seen it. Does any one know a reference?