Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 8/7/84; site ucbvax.ARPA Path: utzoo!watmath!clyde!burl!ulysses!ucbvax!wildbill From: wildbill@ucbvax.ARPA (William J. Laubenheimer) Newsgroups: net.math Subject: Re: f(x) = (if x = p/q then 1/q else 0) integrable ?? Message-ID: <4467@ucbvax.ARPA> Date: Wed, 30-Jan-85 01:13:54 EST Article-I.D.: ucbvax.4467 Posted: Wed Jan 30 01:13:54 1985 Date-Received: Thu, 31-Jan-85 00:36:18 EST References: <350@decwrl.UUCP> Reply-To: wildbill@ucbvax.UUCP (William J. Laubenheimer) Organization: University of California at Berkeley Lines: 8 Summary: Yes, it is integrable. Any function which is constant almost everywhere (i.e., except on a set of measure 0) is integrable. The integral over any measurable set, such as the ones you gave, is 0. This result holds for any function which is 0 a.e. Bill Laubenheimer ----------------------------------------UC-Berkeley Computer Science ...Killjoy went that-a-way---> ucbvax!wildbill