Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!watmath!clyde!bonnie!akgua!whuxlm!harpo!decvax!cca!ima!ISM780!ed From: ed@ISM780.UUCP Newsgroups: net.math Subject: Re: Orphaned Response Message-ID: <93@ISM780.UUCP> Date: Sun, 17-Feb-85 00:23:52 EST Article-I.D.: ISM780.93 Posted: Sun Feb 17 00:23:52 1985 Date-Received: Mon, 18-Feb-85 05:20:06 EST Lines: 40 Nf-ID: #R:charm:-58600:ISM780:30200001:177600:838 Nf-From: ISM780!ed Feb 14 10:08:00 1985 /* Written 5:20 am Feb 13, 1985 by mam@charm in ISM780:net.math */ A netter asked: 1) What is the sum of 1 + 11 + 111 + ... {n ones} ? 2) At what time between 4:00 and 5:00 do the hour and minute hands of a clock form a right angle? My (possible buggy) solutions: 1) This series contains: n 1's n-1 10's n-2 100's ... 1 10^n. ********************** Your representation is incorrect; e.g., if n=2, you are saying the sum has 2 1's, and 1 100. Obviously, the last one should be "1 10^n-1". Regardless, a far easier way to solve this problem is to realize that each term t in the sum can be expressed as: i i t = 10 - 1 i ------ 9 Then it is easily shown that n --- \ n+1 / t = 10 - 10 - 9n --- i -------------- i=1 81 Ed Lycklama decvax!cca!ima!ism780!ed