Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 beta 3/9/83; site nbs-amrf.UUCP Path: utzoo!linus!philabs!cmcl2!seismo!umcp-cs!nbs-amrf!hopp From: hopp@nbs-amrf.UUCP (Ted Hopp) Newsgroups: net.math Subject: Re: Ashby's solution to 1+11+...n 1's seems to be in error Message-ID: <430@nbs-amrf.UUCP> Date: Sun, 17-Feb-85 15:25:58 EST Article-I.D.: nbs-amrf.430 Posted: Sun Feb 17 15:25:58 1985 Date-Received: Wed, 20-Feb-85 09:26:49 EST References: <595@decwrl.UUCP> Organization: National Bureau of Standards Lines: 24 From: osman@sprite.DEC (Eric Osman, dtn 283-7484) > Subject: Ashby's solution is wrong (to 1+11+111 . . .+ n 1's) > > | Solution to Sn = 1 + 11 + 111 + ... + 11...11 | > > | |<--->| | > > | n 1's | > > | is easily obtained by re-writing as | > > | | > > | (1) Sn = (10^1 - 1)/9 + (10^2 - 1)/9 + ... + (10^n - 1)/9 | > > | | > > | re-arranging terms gives | > > | | > > | (2) Sn = 10*(10^n -1)/81 - n/9 | > > | | > > =========================================================================== > There's something wrong with this solution ! s4 = 1+11+111+1111 = 1234. > Let's check: s4 = 10*(10^4-1)/81 - 4/9 = 10*9999/81 - 4/9 = 1234 + 16/81 - > 4/9 DOES NOT EQUAL 1234 !! [(4/9)^2 = 16/81 but so what] Check your math. 10*9999/81 = 1234 + 36/81, not 1234 + 16/81. -- Ted Hopp {seismo,umcp-cs}!nbs-amrf!hopp