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Posting-Version: version B 2.10.2 9/18/84; site masscomp.UUCP
Path: utzoo!watmath!clyde!bonnie!masscomp!leiby
From: leiby@masscomp.UUCP (Mike Leibensperger)
Newsgroups: net.unix
Subject: Re: "set" question for Bourne shell scripts
Message-ID: <617@masscomp.UUCP>
Date: Thu, 14-Feb-85 14:16:14 EST
Article-I.D.: masscomp.617
Posted: Thu Feb 14 14:16:14 1985
Date-Received: Fri, 15-Feb-85 04:21:42 EST
References: <661@turtlevax.UUCP>
Reply-To: leiby@masscomp.UUCP (Mike Leibensperger)
Distribution: net
Organization: Masscomp - Westford, MA
Lines: 25
Summary: 

In article <661@turtlevax.UUCP> ken@turtlevax.UUCP (Ken Turkowski) writes:
>The Bourne shell allows you to set the positional parameters with:
>	set a b c d e
>so that 
>	$1 yields a
>	$2 yields b
>	$3 yields c
>	$4 yields d
>	$5 yields e
>	$# yields 5
>regardless of the parameters given to the shell script on the command line.
>Now, my question is, how do you remove all parameters, i.e. set $# to 0?

The following works, tho it probably isn't the fastest:

	:
	while [ $# != 0 ]
	do
		echo my $# args are: $*
		shift
	done
--
Mike Leibensperger
Masscomp; 1 Technology Park; Westford, MA 01886
{decvax,harpo,tektronix}!masscomp!leiby