Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site watdaisy.UUCP Path: utzoo!watmath!watdaisy!ndiamond From: ndiamond@watdaisy.UUCP (Norman Diamond) Newsgroups: net.puzzle Subject: Re: a good interview question (the incorrect solution) Message-ID: <7075@watdaisy.UUCP> Date: Fri, 15-Mar-85 10:28:42 EST Article-I.D.: watdaisy.7075 Posted: Fri Mar 15 10:28:42 1985 Date-Received: Sat, 16-Mar-85 02:32:22 EST References: <302@ssc-bee.UUCP> <463@petsd.UUCP> <807@loral.UUCP> Organization: U of Waterloo, Ontario Lines: 24 > *********** > Question: The original question says nothing about time. Why can't you go > 30mph for the first mile and 90mph for the second mile, therefore averaging > out to 60mph. If you are driving along going 30mph for 1 mile and then > 90mph in the next, you are averaging 60mph for the 2 miles. Am I missing > something here? Speed does say something about time and distance. You average 30mph for the first mile, 90mph for the second mile, and 45mph for the total two miles. Alternatively: you average 30mph for the first 120 seconds, 90mph for the next 40 seconds, and 45mph for the total 160 seconds. (If you don't believe this one, take the mean of 30, 30, 30, and 90. If you still don't believe it, then take the mean of 1, 1, 1, 1, 1, 1, 1, 1, 1, and 1001; it is not 501.) -- Norman Diamond UUCP: {decvax|utzoo|ihnp4|allegra}!watmath!watdaisy!ndiamond CSNET: ndiamond%watdaisy@waterloo.csnet ARPA: ndiamond%watdaisy%waterloo.csnet@csnet-relay.arpa "Opinions are those of the keyboard, and do not reflect on me or higher-ups."