Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 (Tek) 9/28/84 based on 9/17/84; site eros.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxt!houxm!vax135!cornell!uw-beaver!tektronix!teklds!eros!shuju From: shuju@eros.UUCP (ju Wang Burgess) Newsgroups: net.puzzle,net.jokes.d Subject: Re: a good interview question Message-ID: <619@eros.UUCP> Date: Fri, 22-Mar-85 13:48:27 EST Article-I.D.: eros.619 Posted: Fri Mar 22 13:48:27 1985 Date-Received: Tue, 26-Mar-85 06:37:32 EST References: <302@ssc-bee.UUCP> <410@cybvax0.UUCP> Distribution: net Organization: Tektronix, Beaverton OR Lines: 31 Xref: watmath net.puzzle:654 net.jokes.d:1011 > In article <302@ssc-bee.UUCP> thill@ssc-bee.UUCP (Tom Hill) writes: > > Here is a good interview problem. It can be a bit heartless to give > > to a nervous interviewee but bewarned... a guy I met was actually > > asked this! > > > > You have to travel from town A. to town B. The distance > > between the two towns is 2 miles. If you drive 30 mph for the > > first mile, how fast do you have to drive the second mile in > > order to average 60 mph? > > There are two simple answers. > > a) You cannot travel fast enough. You have already consumed the entire > two minutes required to average 60 mph over the time it takes to make > the trip. > > b) 90 mph. You will then have travelled an average of 60 mph over the > DISTANCE of the trip. > > There probably are other measures possible as well. > -- > > Mike Huybensz ...decvax!genrad!mit-eddie!cybvax0!mrh *** REPLACE THIS LINE WITH YOUR MESSAGE *** I don't believe that the second solution would work as 'mph' stands for Miles Per Hour, so the average 60 miles is measured over time, NOT DISTANCE. I think (a) is the only possible answer. Shu-Ju