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From: boris@mit-athena.UUCP (Boris N Goldowsky)
Newsgroups: net.physics
Subject: Re: A new improved perpetual motion machine
Message-ID: <159@mit-athena.UUCP>
Date: Mon, 8-Apr-85 18:12:59 EST
Article-I.D.: mit-athe.159
Posted: Mon Apr  8 18:12:59 1985
Date-Received: Thu, 11-Apr-85 00:30:14 EST
References: <489@vax2.fluke.UUCP>
Organization: MIT Project Athena
Lines: 40

I think that this is why the pm machine won't work.

	The suggestion was to put jars on a conveyor belt in water such that
	on the "up" side a weight in each one stretched a membrane thus
 	increasing the volume of the jar and increasing the buoyancy,
	on the "down" side the weight would fall on the other (rigid)
	side of the jar and the buoyancy would decrease.

The way to attack these problems is by considering energy.  Nothing will
by itself go to a higher energy state.

Thus you can think of buoyancy as a force tending to lower the energy state
of something immersed in a fluid.  The pressure at the bottom of the tank
of water is greater than the pressure at the top.  The higher pressure
on the bottom of the jar is what pushes the jar upwards, toward a position
where it would have a lower potential energy.

We know that at least as much energy must be lost in one complete
circuit around the belt as is gained, but it is not obvious where.  Energy
is gained moving the enlarged jars up and also letting them fall back down.
We might guess then that the same amount is lost in the *transition* between
the two states.  It takes a good deal of work (energy) to make the jars
bigger... because you have to displace that volume of water up to the 
surface against gravity.  This work is actually done by gravity, when the
weights inside the jars fall and push down the membranes.  But then
the machine has to do that same amount of work pulling the weights back
up.

Thus the amount of energy gained is equal to the amount of energy lost:
they are both the difference in energy between the extra volume of water
at the top vs. the bottom of the belt:
	( E=Vgh=Volume*density of water*accel. of gravity*height)
and you lose a little to friction so the device won't work at all.


"This isn't speculation, this is predicted fact!"
-- 
Boris Goldowsky     decvax!mit-athena!boris
		    boris@mit-athena.arpa
		    Goldowsky@mit-multics.{arpa,bitnet,mailnet}