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Path: utzoo!watmath!clyde!bonnie!akgua!whuxlm!harpo!decvax!ucbvax!ucbcad!klein
From: klein@ucbcad.UUCP
Newsgroups: net.audio
Subject: Re: Re: question
Message-ID: <172@ucbcad.UUCP>
Date: Fri, 5-Apr-85 11:48:02 EST
Article-I.D.: ucbcad.172
Posted: Fri Apr  5 11:48:02 1985
Date-Received: Sun, 7-Apr-85 03:22:15 EST
References: <458@bonnie.UUCP> <459@umd5.UUCP>
Organization: UC Berkeley CAD Group, Berkeley, CA
Lines: 28

>                Input 1 >-------------< Input 2
>                         \           /
>                          \         /
>                           \       /
>                            \     /
>                             \   /
>                              \ /
>                               |
>                               ^
>                              Load
> 

Oops, doing a quick analysis of this network shows that the load presented
to each amp channel is 7R/11, or in this case, R = 2.7ohms, or 1.72 ohms.
The amp will have a very hard time here, and almost none of that power
makes it to the 8 ohm load.  Also, the load is driven through an R/2
output impedance, so damping factor suffers.

Using a resistive network will always mean losing power and damping factor.
A big transformer is certainly the best way to do this, ideally, but
expensive for good quality.  You could also buy speakers with two voice
coils, if you have that luxury and are only interested in mixing bass.

-- 

		-Mike Klein
		...!ucbvax!ucbmerlin:klein	(UUCP)
		klein%ucbmerlin@berkeley	(ARPA)