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Path: utzoo!linus!philabs!cmcl2!seismo!umcp-cs!cvl!umd5!don
From: don@umd5.UUCP
Newsgroups: net.audio
Subject: Re: Re: Re: question
Message-ID: <465@umd5.UUCP>
Date: Sun, 7-Apr-85 17:10:10 EST
Article-I.D.: umd5.465
Posted: Sun Apr  7 17:10:10 1985
Date-Received: Tue, 9-Apr-85 01:12:52 EST
References: <458@bonnie.UUCP> <459@umd5.UUCP> <172@ucbcad.UUCP>
Organization: U of Md, CSC, College Park, Md
Lines: 42

>>                Input 1 >-------------< Input 2
>>                         \           /
>>                          \         /
>>                           \       /
>>                            \     /
>>                             \   /
>>                              \ /
>>                               |
>>                               ^
>>                              Load
>> 
> Using a resistive network will always mean losing power and damping factor.
> 		-Mike Klein
[]
Ackk ! Attack of The Memory Bug! (Thanks Mike!)
It didn't seem to me that damping factor would be of any consequence for
the asker's application, and since he was using low power anyway (headphones),
and what's a half a watt among friends, anyway?
The revised schematic is:
              Input 1 >---/\/\/\---o---/\/\/\---< Input 2
                                   |
                                   |
                                   |
                                   |
                                   ^
                                  Load
The resistors form either half of the top of the "T" and the "|" portion.
[Look at the referece book before you post something off the top of your
head !!! ... Let that be a lesson to you all !! :^) ]


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