Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site geowhiz.UUCP Path: utzoo!linus!philabs!cmcl2!seismo!uwvax!geowhiz!karsh From: karsh@geowhiz.UUCP (Bruce Karsh) Newsgroups: net.math Subject: Normalization for DFT Message-ID: <175@geowhiz.UUCP> Date: Mon, 8-Apr-85 00:09:46 EST Article-I.D.: geowhiz.175 Posted: Mon Apr 8 00:09:46 1985 Date-Received: Tue, 9-Apr-85 03:36:37 EST Distribution: net Organization: UW Madison, Geology Dept. Lines: 45 The DFT (Discrete Fourier Transform) is usually defined as: N ------ -2 PI i m n \ ----------- FORWARD TRANSFORM: F(n) = > f(m) e N / ------ m=0 N ------ 2 PI i m n 1 \ ---------- REVERSE TRANSFORM: f(m) = - > F(n) e N N / ------ n=0 Why is that? Wouldn't it make more sense to normalize both the forward and inverse transforms with (1/sqrt(N))? Like this: N ------ -2 PI i m n 1 \ ----------- FORWARD TRANSFORM: F(n) = ----- > f(m) e N sqrt(N) / ------ m=0 N ------ 2 PI i m n 1 \ ---------- REVERSE TRANSFORM: f(m) = ----- > F(n) e N sqrt(N) / ------ n=0 This way looks more symetrical. Besides, when you do it this way, the sum of the sqares of all the transformed coefficients equals the sum of the squares of all the un-transformed coeffiecients. So why do people define it the other way? -- Bruce Karsh | U. Wisc. Dept. Geology and Geophysics | 1215 W Dayton, Madison, WI 53706 | This space for rent. (608) 262-1697 | {ihnp4,seismo}!uwvax!geowhiz!karsh |