Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site brl-tgr.ARPA Path: utzoo!watmath!clyde!bonnie!akgua!sdcsvax!dcdwest!ittvax!decvax!genrad!panda!talcott!harvard!seismo!brl-tgr!gwyn From: gwyn@brl-tgr.ARPA (Doug Gwyn ) Newsgroups: net.puzzle Subject: Re: More on Interview Questions...derivative of x! Message-ID: <9551@brl-tgr.ARPA> Date: Thu, 28-Mar-85 15:27:21 EST Article-I.D.: brl-tgr.9551 Posted: Thu Mar 28 15:27:21 1985 Date-Received: Tue, 2-Apr-85 00:14:38 EST References: <379@cavell.UUCP> <917@utcsri.UUCP> <541@lsuc.UUCP> Distribution: net Organization: Ballistic Research Lab Lines: 34 > > ... A question one > > could ask is can you really find ALL functions, defined in any way, > > that equal their derivatives and which are they? > > I think the exponential is the only one, but I don't know. Suppose f(.) and g(.) are any two such functions. Df = f Dg = g D(f - g) = Df - Dg (by linearity of D) = f - g So (f - g) is another such function. So what? Well, it's cute. I think a uniqueness proof could be based on it. However, let's assume the availability of a text on ODEs: Let f(.) be such a function of its single (real) argument. Df = f Df - f = 0 (D - 1.)f = 0 (linear (not just affine) operators) Two C-infinity solutions: (A) f == 0 (constant-zero function) (B) f == c exp(.) where c is any constant ((B) includes (A) as a special case, actually) The theory of linear ODEs tells us that (B) is the most general solution under very general continuity assumptions.