Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/5/84; site spp1.UUCP Path: utzoo!watmath!clyde!bonnie!akgua!sdcsvax!sdcrdcf!trwrb!trwspp!spp1!johnston From: johnston@spp1.UUCP (Micheal L. Johnston) Newsgroups: net.astro Subject: Re: Re: StarDate: March 28 Goodbye Venus Message-ID: <183@spp1.UUCP> Date: Thu, 11-Apr-85 13:35:42 EST Article-I.D.: spp1.183 Posted: Thu Apr 11 13:35:42 1985 Date-Received: Sun, 14-Apr-85 02:32:54 EST References: <6@utastro.UUCP> <181@tektools.UUCP> <580@lsuc.UUCP> <7425@watrose.UUCP> Organization: TRW, Redondo Beach CA Lines: 36 > > > What is the highest Venus ever gets? > > Simplifying the > > orbits to coplanar circles, this occurs when the Earth-Venus-Sun angle is > > 90 degrees. (Oddly enough, this situation was also described in net.puzzle > > a couple of months ago -- with respect to clock hands instead of planets!) > > Mark Brader > > Before you go and brush up on your spherical geometry (I boo-booed and deleted > his comment on that) you should brush up on your planar geometry. Your > statement about highest angle above the horizon at 90 degrees is a gross > oversimplification. All you have to do to show this is draw the orbit of > Venus on paper (admittedly a big sheet of paper); pick a position for the > earth; and draw the hypotenuse of your 90 degree triangle. > > You'll find that the hyp. passes inside the orbit of Venus. Using > circular co-planar orbits and no atmosphere, etc., the maximum angle > above the horizon is found by drawing a line from the earth TANGENTIAL > to the orbit of Venus (again, a very long line). > > larry fast (Universty of Waterloo) > broadcasting from exile Maybe I missed something but I thought Mark's posting was correct. The hypotenuse to his 90 degree triangle SHOULD pass inside the orbit of Venus since it's going straight to the sun. Your steps to find the maximum angle only draw a line, so I'll assume the second line is the line tanget to the earth's surface at the observation point to the sun at sunset time. (I think mark stated that 'how high' meant the angle at the time the sun goes down). This second line is the hypotenuse were talking about however, so if you're truly talking about a different angle, I missed. Remember, Mark's hypotenuse IS the earth's orbital radius. Venus' orbital radius is then the closing line and the arcsin of this ratio (Venus' figure on top) would be the angle in question. Mike Johnston