Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site watdaisy.UUCP Path: utzoo!watmath!watdaisy!gjerawlins From: gjerawlins@watdaisy.UUCP (Gregory J.E. Rawlins) Newsgroups: net.math,net.puzzle Subject: Re: needed:algorithm Message-ID: <7204@watdaisy.UUCP> Date: Sun, 21-Apr-85 15:43:24 EST Article-I.D.: watdaisy.7204 Posted: Sun Apr 21 15:43:24 1985 Date-Received: Mon, 22-Apr-85 00:40:49 EST References: <1418@aecom.UUCP> <288@faron.UUCP> Reply-To: gjerawlins@watdaisy.UUCP (Gregory J.E. Rawlins) Distribution: net Organization: U of Waterloo, Ontario Lines: 14 Xref: watmath net.math:1945 net.puzzle:754 In article <288@faron.UUCP> bs@faron.UUCP (Robert D. Silverman) writes: >> Find the smallest integer which can be broken up into: >> a^4 + b^4 = k >> c^4 + d^4 = k >> David Suna > >I'll start by giving you a hint: since it's the sum of two fourth powers >and must be odd it is necessarily of the form 8n+1. The reasoning behind this conclusion escapes me. Why must it be odd? -- Gregory J.E. Rawlins, Department of Computer Science, U. Waterloo {allegra|clyde|linus|inhp4|decvax}!watmath!watdaisy!gjerawlins