Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/5/84; site yale.ARPA Path: utzoo!linus!philabs!cmcl2!seismo!harvard!talcott!panda!genrad!decvax!yale!andrews From: andrews@yale.ARPA (Thomas O. Andrews) Newsgroups: net.math Subject: Re: cardinality of the unit square & the unit line Message-ID: <457@yale.ARPA> Date: Wed, 1-May-85 13:42:30 EDT Article-I.D.: yale.457 Posted: Wed May 1 13:42:30 1985 Date-Received: Sat, 4-May-85 05:20:11 EDT References: <1767@decwrl.UUCP> <72@harvard.ARPA> <54@utastro.UUCP> <536@gloria.UUCP> Reply-To: andrews@yale-comix.UUCP (Thomas O. Andrews) Organization: Yale University CS Dept., New Haven CT Lines: 25 Summary: Expires: Sender: Followup-To: Distribution: Keywords: In article <536@gloria.UUCP> colonel@gloria.UUCP (Col. G. L. Sicherman) writes: > >Of course not. If it were one-to-one and continuous, it would be a >homeomorphism--the line and the square would be topologically the same. > . > . > . >Col. G. L. Sicherman >...{rocksvax|decvax}!sunybcs!colonel This statement is accurate, but somewhat misleading. A map is a homeo- morphism if it is 1-1, continuous, and has a continuous inverse. In general 1-1 and continuous does not imply that the inverse is continuous. For example, the map f:[0,2*pi)-->circle defined by f(a)=(cos a,sin a) is 1-1 and continuous, but certainly not a homeomorphism. On the other hand, if f:X-->Y is 1-1 and continuous, and X is compact, then the inverse of f is also continuous, and hence f is a homeomorphism. Since the unit interval is compact, the Col. Sicherman's statement is accurate. -- Thomas Andrews 17? My dear, what worthless, superstitious nonsense!