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From: lspirkov@udenva.UUCP (Goldilocks)
Newsgroups: net.puzzle
Subject: x^x^x^...=2
Message-ID: <578@udenva.UUCP>
Date: Tue, 30-Apr-85 14:10:15 EDT
Article-I.D.: udenva.578
Posted: Tue Apr 30 14:10:15 1985
Date-Received: Fri, 3-May-85 07:41:37 EDT
Distribution: net
Organization: U of Denver
Lines: 15

x^x^x^x ... = x^(x^x^...) = x^2 = 2 , therefore, x=sqrt(2);

someone posted a comment about how x couldn't equal sqrt(2)
because that goes to infinity so x should probably equal sqrt (-2).
no, it doesn't go to infinity because exponentiation associates
right to left so you wouldn't get something like:
	sqrt(2) ^ sqrt(2) ^ sqrt (2) = 2
because that's really
	sqrt(2) ^ (sqrt(2) ^ sqrt(2)) ~ 1.76.

-- 

					Goldi

email:  udenva!lspirkov