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Path: utzoo!linus!philabs!cmcl2!seismo!harvard!bbnccv!keesan
From: keesan@bbnccv.UUCP (Morris M. Keesan)
Newsgroups: net.micro.68k,net.lang.c
Subject: Re: Question of Ignorance
Message-ID: <481@bbnccv.UUCP>
Date: Wed, 15-May-85 10:55:20 EDT
Article-I.D.: bbnccv.481
Posted: Wed May 15 10:55:20 1985
Date-Received: Thu, 16-May-85 21:45:21 EDT
References: <198@unccvax.UUCP> <1427@bbncca.ARPA> <5590@utzoo.UUCP> <762@turtlevax.UUCP>
Organization: Bolt Beranek and Newman, Cambridge, MA
Lines: 21
Xref: linus net.micro.68k:707 net.lang.c:4718

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> > > ... I recommend using one of the two constructs
> > > 
> > >     ( longptr == (long *)32 )
> > > or  ( (int)longptr == 32 )
> > > 
> > > which are guaranteed to do what you want ...
> >
> >Argh, WRONG!!  Turn that "(int)" into "(long)" and I might agree.  You
> >have no guarantees that an int is long enough to hold a pointer.
> 
> Arghh!  Wrong again.  You can't cast an lvalue, so that the second option
> is not available.  You MUST say		longptr = (long *)32;
----------------------------------------
HUH?  Of course you can cast an lvalue.  It's just not an lvalue when you get
through casting it.  You're confusing == (equality operator, which is what we
were discussing) with = (assignment operator, which is what you're discussing).
-----------------
Morris M. Keesan
{ihnp4,decvax,etc.}!bbncca!keesan
keesan@bbn-unix.ARPA