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Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxt!houxm!ihnp4!tellab1!tellab3!thoth
From: thoth@tellab3.UUCP (Marcus Hall)
Newsgroups: net.cooks
Subject: Re: freezing hot water
Message-ID: <260@tellab3.UUCP>
Date: Wed, 29-May-85 19:14:13 EDT
Article-I.D.: tellab3.260
Posted: Wed May 29 19:14:13 1985
Date-Received: Fri, 31-May-85 04:18:57 EDT
References: <188@sdcarl.UUCP> <10500002@haddock.UUCP> <115@illogica.UUCP>
Reply-To: thoth@tellab3.UUCP (Marcus Hall)
Organization: Tellabs, Inc., Lisle, IL
Lines: 31
Summary: 

>The rate at which a liquid approaches temperature equilibrium with
>it's environment is related to the difference in temperature between
>the liquid and it's environment.
>
...
>So, hot water cools ~faster~ than an equal volume of cold water
>because the temperature difference between it and it's environment
>is greater.

Yes, but when the hot water reaches the temperature that the cold water
was when it was put in, the ex-hot water cools at the same rate as the
cold water did, but by now the cold water is even colder.  The hot water
may cool faster, but it has farther to go!

>"But... But... wait!", you exclaim. "There exists a point at which
>the ~hot~ water will be the same temperature as the cold! After that
>point the temperature difference will be equal and they should cool
>at the same rate."

The point at which the temperatures are equal is when the ex-hot water
freezes and reaches the same temperature as the cold ex-(liquid)water.

>Yes, but the volume of the hot water will be ~less~ because some of
>the hot water will have evaporated by that time. Since there is less
>water to freeze, it freezes faster.

So start out with less cold water in the first place!

Really, is this serious?

marcus hall