Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.3 alpha 4/15/85; site leadsv.UUCP Path: utzoo!decvax!genrad!panda!talcott!harvard!seismo!hao!hplabs!pesnta!amdcad!cae780!leadsv!morse From: morse@leadsv.UUCP (Terry Morse) Newsgroups: net.physics Subject: A thought experiment on freezing water Message-ID: <455@leadsv.UUCP> Date: Thu, 23-May-85 13:47:22 EDT Article-I.D.: leadsv.455 Posted: Thu May 23 13:47:22 1985 Date-Received: Sun, 26-May-85 16:40:10 EDT Distribution: na Organization: LMSC, Sunnyvale CA Lines: 38 Keywords: water,cooling,heat There has been a discussion in net.cooks (of all places) of whether or not it is possible to freeze hot water faster than cold water, all else being equal. There have been several explanations as to why it might happen. Some people have even done experiments. I would like to pose this as a problem and see if anybody has a solution. I want to know under what conditions hot water will freeze faster than cold. The energy transport mechanisms to consider are: 1) evaporative heat loss (and evaporative mass transfer) 2) convective heat loss (consider h = constant to simplify) The container should be thought of as a rectangular cube with the top side exposed to the air (your basic ice cube tray). As a start, think of the following relationships: mass loss = f ( T difference, surface area, humidity ) convective loss = f ( T difference alone (simplification) ) A simple form of the differential equation may be written in the form outflow - inflow + change in storage = 0, or: q(conv) + q(evap) + c d/dt( M Tw ) = 0 q(conv) = convective heat loss rate = h (Tw - Ta) q(evap) = evaporative heat loss rate = ? M = mass of water c = specific heat of water (assume constant) Tw = temperature of water Happy gedanken experimenting!!! -- Terry Morse (408)743-1487 UUCP: { (ucbvax!dual!sun) | (ihnp4!qubix) } !sunncal!leadsv!morse UUCP: { allegra | ihnp4 | dual } !fortune!amdcad!cae780!leadsv!morse