Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP
Posting-Version: version B 2.10.2 9/18/84; site utastro.UUCP
Path: utzoo!linus!philabs!cmcl2!seismo!umcp-cs!gymble!lll-crg!dual!mordor!ut-sally!utastro!ethan
From: ethan@utastro.UUCP (Ethan Vishniac)
Newsgroups: net.sf-lovers
Subject: Re: SDIII: TSfS
Message-ID: <122@utastro.UUCP>
Date: Thu, 23-May-85 10:53:29 EDT
Article-I.D.: utastro.122
Posted: Thu May 23 10:53:29 1985
Date-Received: Sat, 25-May-85 06:42:33 EDT
References: <2074@topaz.ARPA>
Organization: U. Texas, Astronomy, Austin, TX
Lines: 26

> > Enterprise, its distance is reported as being 5000 kilograms(!!) No
> doubt I should explain this one two.  This is due to the revolutionary
> theory of "Berglundic relativity," which has as a consequence that
> D=mb^2, so that just as now physicists talk about masses (of elementary
> particles) in terms of Bev's and Gev's (units of energy), in the
> twenty-third century, they refer to distances in terms of mass.  (:-),
> in case you hadn't guessed.)

Actually, one can already translate between mass and distance as the two
are related directly to one another in two different ways.

One, in GR there is an equivalence given by MassxNewton's constant/c^2=distance
A distance of 5000 kilograms is therefore about 3x10^-22 centimeters!
  :-)

Two, perhaps they meant the Compton wavelength of that amount of mass.
In this case Distance= Planck's constant/(massxc).  In this way we obtain
about 10^-44 centimeters.

Either way we see that the cloaking device is amazingly effective at close
quarters!

"Don't argue with a fool.      Ethan Vishniac
 Borrow his money."            {charm,ut-sally,ut-ngp,noao}!utastro!ethan
                               Department of Astronomy
                               University of Texas