Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/5/84; site gloria.UUCP Path: utzoo!watmath!clyde!burl!ulysses!gamma!epsilon!zeta!sabre!bellcore!decvax!genrad!grkermi!panda!talcott!harvard!seismo!rochester!rocksanne!sunybcs!gloria!colonel From: colonel@gloria.UUCP Newsgroups: net.math Subject: Re: no more volume of a tetrahedron Message-ID: <811@gloria.UUCP> Date: Sat, 8-Jun-85 14:06:21 EDT Article-I.D.: gloria.811 Posted: Sat Jun 8 14:06:21 1985 Date-Received: Tue, 11-Jun-85 03:54:57 EDT References: <758@gloria.UUCP> <5847@ucla-cs.ARPA> Distribution: net Organization: SUNY-Buffalo Computer Sci. Lines: 17 ["Mathematicians are a kind of Frenchmen ... "] > For this particular problem, all you > need to find is M, which transforms the standard tetrahedron to > whatever tetrahedron you want. For the tetrahedron P,Q,R,S: > > 1 | [P-S 0]| 1 | [P 1]| > V = --- |det[Q-S 0]| = --- |det[Q 1]| > 6 | [R-S 0]| 6 | [R 1]| > | [ S 1]| | [S 1]| I asked for the volume in terms of the lengths of the edges, not the positions of the vertices! Anyway, it's been answered, so please, no more. -- Col. G. L. Sicherman ...{rocksvax|decvax}!sunybcs!colonel