Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 5/3/83; site ukc.UUCP Path: utzoo!watmath!clyde!bonnie!akgua!whuxlm!harpo!decvax!genrad!panda!talcott!harvard!seismo!mcvax!ukc!ptb From: ptb@ukc.UUCP (P.T.Breuer) Newsgroups: net.math Subject: Re: Euler's(?) formula Message-ID: <5259@ukc.UUCP> Date: Tue, 18-Jun-85 23:18:49 EDT Article-I.D.: ukc.5259 Posted: Tue Jun 18 23:18:49 1985 Date-Received: Fri, 21-Jun-85 01:56:23 EDT References: <1832@ut-ngp.UTEXAS> Reply-To: ptb@ukc.UUCP (PUT YOUR NAME HERE) Distribution: net Organization: Computing Laboratory, U of Kent at Canterbury, UK Lines: 24 In article <1832@ut-ngp.UTEXAS> graner@ut-ngp.UTEXAS (Nicolas Graner) writes: >I think it was Euler who showed that a polyhedron with F faces, >V vertices and E edges satisfies the relation: F + V = E + 2. > >I have seen a very technical proof, but the result is so simple and >beautiful that there should be a simple and beautiful proof (i.e. >accessible to non mathematicians). Does anyone know of such a proof? >Also, to what kind of polyhedrons does it apply (convex, connected...) ? > >Nic. {ihnp4,seismo,allegra,...}!ut-ngp!graner > >*If Murphy's law can go wrong, it won't* I assume the technical proof you've seen is Poincare's, which translates the problem into what's now called homology theory. (The basic idea being to define vector spaces generated by the faces, edges and vertices, and consider the kernels and images of the boundary maps between these spaces.) I don't know of a simpler, general proof. There are several proofs which look very plausible and work for (usually unspecified) special cases. You can find many of these in a beautiful book "Proofs and Refutations" by Imre Lakatos. The book uses the history of this problem to illustrate Lakatos's ideas on the philosophy and history of mathematics. Thoroughly recommended to mathematicians and interested bystanders alike.