Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/5/84; site cvl.UUCP Path: utzoo!linus!philabs!cmcl2!seismo!umcp-cs!cvl!david From: david@cvl.UUCP (David Harwood) Newsgroups: net.math Subject: Euler formula Message-ID: <554@cvl.UUCP> Date: Mon, 17-Jun-85 14:06:33 EDT Article-I.D.: cvl.554 Posted: Mon Jun 17 14:06:33 1985 Date-Received: Fri, 21-Jun-85 07:27:13 EDT Distribution: net Organization: Computer Vision Lab, U. of Maryland, College Park Lines: 27 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ >From: graner@ut-ngp.UTEXAS (Nicolas Graner) Newsgroups: net.math Subject: Euler's(?) formula Message-ID: <1832@ut-ngp.UTEXAS> I think it was Euler who showed that a polyhedron with F faces, V vertices and E edges satisfies the relation: F + V = E + 2. I have seen a very technical proof, but the result is so simple and beautiful that there should be a simple and beautiful proof (i.e. accessible to non mathematicians). Does anyone know of such a proof? Also, to what kind of polyhedrons does it apply (convex, connected...) ? Nic. {ihnp4,seismo,allegra,...}!ut-ngp!graner ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ There is an intuitive constructive 'proof': Verify that the formula is true for a trivial 'object'; supposing that any object may be constructed from this with the addition of vertices, we observe that if the added vertex splits an edge, then F + (V+1) = (E+1) + 2, else if it splits a face, then (F+2) + (V+1) = (E+3). (Of course, I am ignoring the holomogy of these 'objects'.)