Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site charm.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxn!charm!mam From: mam@charm.UUCP (Matthew Marcus) Newsgroups: net.physics Subject: Self-gravitating Photons Message-ID: <681@charm.UUCP> Date: Mon, 10-Jun-85 22:26:41 EDT Article-I.D.: charm.681 Posted: Mon Jun 10 22:26:41 1985 Date-Received: Tue, 11-Jun-85 07:28:04 EDT Organization: Physics Research @ AT&T Bell Labs Murray Hill NJ Lines: 21 (E = Mc^2 +- 3dB ) About maximum energies for photons: Take any ol' photon you have lying around. Now look at it from a frame of reference going very fast in the direction opposite to said photon. The photon is now blue-shifted to higher energy. By making your new reference frame move fast enough, you can get any energy you want, including 10^43 Hz or whatever the last-posted limit was. Now, 'black-hole-ness' is an invariant, so an energetic photon is never a black hole. Another way to see this is that black holes are characterized by three and only three parameters: charge, spin, and mass. This mass is an invariant, and hence must be in the nature of a rest mass. The rest mass of a photon, any photon is 0. 'Nuff said. The argument has been made that a hefty enough electromagnetic field will gravitate itself into a black hole. Well, Misner, Thorne & Wheeler, aka the Phone Book, give as a show-that problem the theorem that two light beams do not attract. While there is energy density in each beam (T sub 00, where T is the stress-energy tensor), there is also momentum density (T sub 0i) which cancels out the attractive effects of light upon light. Therefore, you are not going to get a black hole by shining lots of light into a small spot. {BTL}!charm!mam