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Path: utzoo!linus!philabs!cmcl2!seismo!brl-tgr!tgr!ddaly%xls-plexus01.amc@AMC-HQ.ARPA
From: ddaly%xls-plexus01.amc@AMC-HQ.ARPA (DUSTY)
Newsgroups: net.unix-wizards
Subject: AWK question
Message-ID: <435@brl-tgr.ARPA>
Date: Mon, 5-Aug-85 11:50:33 EDT
Article-I.D.: brl-tgr.435
Posted: Mon Aug  5 11:50:33 1985
Date-Received: Wed, 7-Aug-85 01:56:49 EDT
Sender: news@brl-tgr.ARPA
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Does anyone know if and how I can get awk to do a >= (less than or equal)
on a value entered from a terminal by the user?
E.G.
echo 'enter date in format yy-mm-dd \c $dt'
read  dt
echo $dt
awk '$5  >= $dt ' .suspfile >xout

awk seems to ignore the terminal entered data. Is there any way to get
awk to recognize this kind of variable?

ed daly
ddaly at amc-hq