Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site mips.UUCP Path: utzoo!linus!decvax!decwrl!Glacier!mips!kim From: kim@mips.UUCP (Kim DeVaughn) Newsgroups: net.physics Subject: Re: cancelling forces Message-ID: <195@mips.UUCP> Date: Sun, 22-Sep-85 23:49:41 EDT Article-I.D.: mips.195 Posted: Sun Sep 22 23:49:41 1985 Date-Received: Wed, 25-Sep-85 11:43:37 EDT References: <546@sri-arpa.ARPA> Organization: mips ... where RISC is a way of life Lines: 34 [ ... go ahead, eat my bits ... ] > From: Kenneth Sloan > Here's a new subject to think about, start aguments, etc. > > Let's say I have a robot that pushes a box. I put a certain amount of > > Now I set up another one of these, and place it alongside the first > robot. I have them push in the same direction so that the forces add. > > the pushes will cancel. Now I appear to be getting no energy out of > this system, at least not in the form of a moving box. I am still > putting as much energy into the system. All I did was move one of the > devices. What is happening to the energy? Is there an output in > another form of energy? Is it building up in one of the devices Heat. If your robot's motors have sufficient torque, their treads (or wheels, or whatever) will "slip" against the surface they're "pushing against" (i.e., friction). Less torque, and the motors will heat up due to "electrical friction" (i.e., hysteresis, I-square*R losses, etc.) The surface is part of the system (and if it were "removed," you'd have your robots in space, and there would be no motion irrespective of which side the 'bots were on). /kim > -Ken Sloan *** REPLACE THIS LINE WITH YOUR MESSAGE *** -- UUCP: {decvax,ucbvax,ihnp4}!decwrl!mips!kim DDD: 415-960-1200 USPS: MIPS Computer Systems Inc, 1330 Charleston Rd, Mt View, CA 94043 Brought to you by Super Global Mega Corp .com