Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site cisden.UUCP Path: utzoo!linus!philabs!cmcl2!seismo!hao!nbires!boulder!cisden!phillips From: phillips@cisden.UUCP (Tom Phillips) Newsgroups: net.startrek Subject: Re: Vulcan arithmetic Message-ID: <290@cisden.UUCP> Date: Mon, 21-Oct-85 13:37:10 EDT Article-I.D.: cisden.290 Posted: Mon Oct 21 13:37:10 1985 Date-Received: Thu, 24-Oct-85 06:08:02 EDT References: <1137@rayssd.UUCP> <298@utflis.UUCP> <199@astroatc.UUCP> Reply-To: phillips@cisden.UUCP (Tom Phillips) Distribution: net Organization: ConTel Information Systems, Denver Lines: 17 Keywords: seven tenths >>In article <1137@rayssd.UUCP> m1b@rayssd.UUCP (M. Joseph Barone) writes: >>> In 'Errand of Mercy', where Kirk and Spock try to help >>>the Organians from Klingon domination, Spock computes their odds >>>of success to be some_large_number.7 to 1. I want to know where >>>the .7 came from. Any number divided by 2 will have either an >>>integral quotient or a quotient with a remainder of one (0.5). Who says that the odds against success are strictly (# of enemies)/(# of friendlies)? Perhaps there were modifications for armament, organization, desperation, historical precedents? In any case, "(some large number).7 to 1" is totally bogus. Too much uncertainty in the calculations. Perhaps the writers left out a :-)? Tommy Phillips cisden!phillips