Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.3 4.3bsd-beta 6/6/85; site turtlevax.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxt!houxm!vax135!petsd!peora!pesnta!amd!turtlevax!ken From: ken@turtlevax.UUCP (Ken Turkowski) Newsgroups: net.math Subject: Re: Surface Area Query Message-ID: <964@turtlevax.UUCP> Date: Mon, 18-Nov-85 14:55:05 EST Article-I.D.: turtleva.964 Posted: Mon Nov 18 14:55:05 1985 Date-Received: Thu, 21-Nov-85 03:41:22 EST References: <749@h-sc1.UUCP> Reply-To: ken@turtlevax.UUCP (Ken Turkowski) Distribution: net Organization: CIMLINC, Inc. @ Menlo Park, CA Lines: 32 In article <749@h-sc1.UUCP> riggsby@h-sc1.UUCP (andrew riggsby) writes: >Is there a general method for determining the surface area of an arbitrary >surface or solid similar to (or not similar, for that matter) using >displacement to determine the volume of a solid. Note that this includes >2-d surfaces in E^3. If you can determine the normal to the surface, you can use the divergence theorem: __ integral \/ . A dV = integral A . n dS V S Where V is the entire volume of the object, S is the surface of the object, __ \/ is the vector differential operator "del", . is the dot product, dV is an incremental volume of integration, dS is an incremental surface of integration, n is the normal to the surface, and A is a vector function. For your purposes, you would want to pick a function A such that A.n == 1 In some applications, doing a surface integral is easier than a volume integral; hopefully, for yours, a volume integral is easier. -- Ken Turkowski @ CIMLINC (formerly CADLINC), Menlo Park, CA UUCP: {amd,decwrl,hplabs,seismo,spar}!turtlevax!ken ARPA: turtlevax!ken@DECWRL.DEC.COM