Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 GARFIELD 20/11/84; site garfield.UUCP Path: utzoo!utcsri!garfield!robertj From: robertj@garfield.UUCP Newsgroups: net.math Subject: Re: Surface Area Query Message-ID: <4407@garfield.UUCP> Date: Wed, 20-Nov-85 08:40:57 EST Article-I.D.: garfield.4407 Posted: Wed Nov 20 08:40:57 1985 Date-Received: Thu, 21-Nov-85 19:43:00 EST References: <749@h-sc1.UUCP> Sender: paulc@garfield.UUCP Reply-To: robertj@garfield.UUCP (Robert Janes) Distribution: net Organization: Memorial U. of Nfld. C.S. Dept., St. John's Lines: 36 Summary: In article <749@h-sc1.UUCP> riggsby@h-sc1.UUCP (andrew riggsby) writes: >Is there a general method for determining the surface area of an arbitrary sur- face or solid similar to (or not similar, for that matter) using displacement >to determine the volume of a solid. Note that this includes 2-d surfaces in >E^3. > >Thanks. > > Andrew Riggsby > riggsby@harvunxu > If the surface is given in parametric form and is of the class C^2 then there is a method that I know of which is good for arbitrary dimensions. It involves the (n-1)th integral (i.e. in E^3 this is the double integral) of the determinant of the metric tensor of the surface. In more detail, let the surface be parametrized by: R = Xi = Xi(U1,U2,...,U(n-1)) let Ri designate the partial derivative of R with respect to the ith coordinate,Ui. Then Gij = Ri.Rj where Ri.Rj is the usual scalar product or dot product. All such Gij define a matrix with dterminant G. If we let I denote the the (n-1)th integral (that is double integrals for E^3, triple integrals for E^4) then if S is the surface area of the surface in question and is given by: S = I{ (G)^(1/2) dU1dU2dU3...dU(n-1) } over the region in question (that is the set on which each Ui is defined ). This I think is what you are looking for and I think that it is correct inwhat it is saying. If not humblest apologies. Reference: Manfredo P. do Carmo, The Differential Geometry of Curves and Surfaces. Cheers Robert Janes