Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site spar.UUCP Path: utzoo!watmath!clyde!burl!ulysses!unc!mcnc!decvax!decwrl!spar!dole From: dole@spar.UUCP (Harry Dole) Newsgroups: net.math Subject: Re: Can you prove/disprove this? Message-ID: <687@spar.UUCP> Date: Mon, 2-Dec-85 14:53:51 EST Article-I.D.: spar.687 Posted: Mon Dec 2 14:53:51 1985 Date-Received: Thu, 5-Dec-85 05:39:47 EST References: <34080@lanl.ARPA> Reply-To: dole@max.UUCP (Harry Dole) Distribution: net Organization: Yoyodyne Semicunduktur - Where the Futur is Tomorro Lines: 27 Summary: In article <34080@lanl.ARPA> dxm@lanl.ARPA writes: >that numbers of the form > > x = 2^(n-1) * (2^n - 1) > >are perfect if n is a prime number. This was true up to the largest >integer the machine could represent. > > > Doug Miller dxm@lanl.arpa > ....!ihnp4!lanl!dxm This looks like the standard characterization of perfect numbers but not quite: If 2^n - 1 is prime, then x = ( 2^n - 1 ) * ( 2^(n-1) ) is perfect and every even perfect number has this form. It is rumoured that even Euclid knew the first part of this one. Note that for n=4 we have x = 120. Let sigma(y) denote the sum of all positive divisors of y - e.g., sigma(6)=1+2+3+6. Then y is perfect if sigma(y)=2*y. However, sigma(120)=3*120 so 120 is referred to as 3-perfect, not perfect. Did you run this on a 2 bit computer? Harry Dole - Long Live the Categorical Imperative