Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site lanl.ARPA Path: utzoo!watmath!clyde!bonnie!akgua!gatech!seismo!cmcl2!lanl!dxm From: dxm@lanl.ARPA Newsgroups: net.math Subject: Re: Can you prove/disprove this? Message-ID: <34214@lanl.ARPA> Date: Tue, 3-Dec-85 11:25:36 EST Article-I.D.: lanl.34214 Posted: Tue Dec 3 11:25:36 1985 Date-Received: Thu, 5-Dec-85 06:49:38 EST References: <34080@lanl.ARPA> <687@spar.UUCP> Distribution: net Organization: Los Alamos National Laboratory Lines: 22 > In article <34080@lanl.ARPA> dxm@lanl.ARPA writes: > >that numbers of the form > > > > x = 2^(n-1) * (2^n - 1) > > > >are perfect if n is a prime number. This was true up to the largest > >integer the machine could represent. > > > It is rumoured that even Euclid knew the first part of this one. Note > that for n=4 we have x = 120. Let sigma(y) denote the sum of all > positive divisors of y - e.g., sigma(6)=1+2+3+6. Then y is perfect > if sigma(y)=2*y. However, sigma(120)=3*120 so 120 is referred to as > 3-perfect, not perfect. Did you run this on a 2 bit computer? Actually I ran it on a Radio Shack Color Computer ( Motorola 6809 ) using a simple 16 bit integer representation scheme. I think the reason I didn't catch the "n=4, therefore x=120 which isn't perfect" error is that 4 isn't prime to begin with....so of course I didn't use it. Yours for care in reading the question, :-) Doug Miller