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From: jeff@hpcnoe.UUCP
Newsgroups: net.games.board
Subject: Dice throwing probabilities
Message-ID: <37800024@hpcnoe.UUCP>
Date: Mon, 16-Dec-85 13:39:00 EST
Article-I.D.: hpcnoe.37800024
Posted: Mon Dec 16 13:39:00 1985
Date-Received: Fri, 20-Dec-85 05:41:51 EST
Organization: 16 Dec 85 11:39:00 MST
Lines: 37


Surprisingly,   there  seems  to  be  some  confusion   about  what  the
probabilities  of  throwing  certain  number  with two dice.  This is an
attempt  to  settle  the  matter  (so  we  can  get  these   rail  baron
probabilities down).

The  simplest way I can explain it is that the two dice are  independent
of each other (one does not affect the other),  therefore  the different
possible rolls are show in the following table:

	1  2  3  4  5  6
	----------------
    1 | 2  3  4  5  6  7
    2 | 3  4  5  6  7  8
    3 | 4  5  6  7  8  9
    4 | 5  6  7  8  9 10
    5 | 6  7  8  9 10 11
    6 | 7  8  9 10 11 12

There are 36 entries in the table,  equally  likely to be thrown.  There
are 2 entries for 3, therefore the  probability of throwing a 3 would be
2/36 = 5.56%.  This can be summarized as:

    2 : 1/36 =  2.78%
    3 : 2/36 =  5.56%
    4 : 3/36 =  8.33%
    5 : 4/36 = 11.11%
    6 : 5/36 = 13.89%
    7 : 6/36 = 16.67%
    8 : 5/36 = 13.89%
    9 : 4/36 = 11.11%
   10 : 3/36 =  8.33%
   11 : 2/36 =  5.56%
   12 : 1/36 =  2.78%

-- Jeff Wu
   ..!ihnp4!hpfcla!j_wu