Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: Notesfiles $Revision: 1.7.0.10 $; site uiucdcsp Path: utzoo!watmath!clyde!cbosgd!ihnp4!inuxc!pur-ee!uiucdcsp!leimkuhl From: leimkuhl@uiucdcsp.CS.UIUC.EDU Newsgroups: net.math Subject: Re: summation in closed form (2^k/k Message-ID: <9600037@uiucdcsp> Date: Sat, 7-Dec-85 17:44:00 EST Article-I.D.: uiucdcsp.9600037 Posted: Sat Dec 7 17:44:00 1985 Date-Received: Tue, 10-Dec-85 06:31:37 EST References: <7512@watdaisy.UUCP> Lines: 18 Nf-ID: #R:watdaisy.UUCP:7512:uiucdcsp:9600037:000:759 Nf-From: uiucdcsp.CS.UIUC.EDU!leimkuhl Dec 7 16:44:00 1985 I think you should have checked your formula out before you post it. The formula you've posted is for Sum{ k / 2^k } not Sum { 2^k / k}. I do not think there is a simple closed form. The above is very simple to derive because Sum{ kx^k } = x Sum{ kx^(k-1) } = x derivative{ Sum{ x^k } }, which has a known simple closed form. The case x=.5 gives us the formula. As I've pointed out in an earlier note, the actual problem involves integrating the formula for Sum{ x^k } (at least if we want a general formula) and this does not seem promising. The Possibility exists that there is a simple closed form for Sum{ 2^k / k }, but not for Sum{ x^k / k }. However, I see no reason why 2 should have such a distinction. -Ben Leimkuhler