Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84 exptools; site ihlpg.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxt!houxm!ihnp4!ihlpg!tan From: tan@ihlpg.UUCP (Bill Tanenbaum) Newsgroups: net.math Subject: Re: Probability question Message-ID: <1478@ihlpg.UUCP> Date: Sat, 14-Dec-85 00:26:17 EST Article-I.D.: ihlpg.1478 Posted: Sat Dec 14 00:26:17 1985 Date-Received: Sat, 14-Dec-85 23:40:00 EST References: <7@hplabsc.UUCP> Organization: AT&T Bell Laboratories Lines: 28 > Upon finding out that I claimed to have been a mathematician once upon a > time, a co-worker asked me a probability question. Now, I never did all > that well in probability or combinatorics, so I am passing this on in > hopes that someone out there might be able to answer it or give me an > appropriate pointer: > > You have two decks of normal playing cards, say red-backed and blue-backed. > You shuffle each individually, and place them on the table. Turn the top > card of each deck face up and place it on the table. Repeat the turning > process until all cards have been turned face up. > > What is the probability that at least one pair of cards turned at the same > time are exactly the same (except for the color of their backs)? > > I think that the problem is equivalent to having a single deck of cards > numbered from 1 to 52 and determining the probability that at least one > card occurs at its numbered position. > > Thanks in advance, > Tim Brengle ------------ The probability is extremely close to 1 - 1/e, or about 63%. The probability that one or more cards will be in their proper position in an N card deck is greater than (1 - 1/e) for odd N, and less than (1 - 1/e) for even N. In either case, the probability approaches the limit of (1 - 1/e) as N increases. -- Bill Tanenbaum - AT&T Bell Labs - Naperville IL ihnp4!ihlpg!tan