Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site decwrl.UUCP Path: utzoo!watmath!clyde!cbosgd!ukma!psuvm.bitnet!psuvax1!burdvax!sdcrdcf!sdcsvax!dcdwest!ittatc!decvax!decwrl!dec-rhea!dec-being!postpischil From: postpischil@being.DEC (Always mount a scratch monkey.) Newsgroups: net.puzzle Subject: Lottery Tickets Message-ID: <28@decwrl.UUCP> Date: Mon, 16-Dec-85 13:55:11 EST Article-I.D.: decwrl.28 Posted: Mon Dec 16 13:55:11 1985 Date-Received: Fri, 20-Dec-85 06:02:25 EST Sender: daemon@decwrl.UUCP Organization: Digital Equipment Corporation Lines: 18 In regard to the lottery-ticket problem, we were first challenged to determine the number of tickets which must be purchased in order to guarantee matching at least a pair. Then we were challenged to determine the number that guarantees a triple. I can see where this is heading, so I will jump to the inevitable conclusion immediately. The number of tickets that must be purchased in order to guarantee matching all six numbers is 1,947,792 (36!/(30!*6!)). (Send mail if you would like a list.) Since the jackpot sometimes exceeds this amount (because of a lack of winners in previous drawings), it may occasionally be a good investment to purchase all 1,947,792 tickets. The only drawback would be the possibility of having to share the money with people who also have a winning ticket. -- edp (Eric Postpischil)