Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site ecsvax.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxt!houxm!whuxl!whuxlm!akgua!mcnc!ecsvax!dgary From: dgary@ecsvax.UUCP (D Gary Grady) Newsgroups: net.puzzle Subject: Re: someone asked why weightless ... Message-ID: <970@ecsvax.UUCP> Date: Fri, 20-Dec-85 13:05:53 EST Article-I.D.: ecsvax.970 Posted: Fri Dec 20 13:05:53 1985 Date-Received: Sun, 22-Dec-85 01:29:49 EST References: <96@decwrl.DEC.COM> Reply-To: dgary@ecsvax.UUCP (D Gary Grady) Organization: Duke U Comp Ctr Lines: 41 I recently posted a puzzlement: If you're in the space shuttle orbiting 300 miles up, the acceleration of gravity is very little less than it is at the surface. If weight = mass X acceleration, how can you be "weightless"? As I noted, the answer to this requires a somewhat more subtle definition than you normally see in general physics texts. In article <96@decwrl.DEC.COM> osman@sprite.DEC (Eric, DIGITAL, Burlington Ma. 617 273-7484) writes: >I believe the key to the answer is the word "orbit". If you're in orbit, >you're whizzing around the earth just fast enough so that your centrifical >force OUTWARD matches gravity's force INWARD. Centrifugal "force" is a fictitious force (measured in figmentive newtons, normally called "fig newtons," but that's beside the point). >Hence the total acceleration for you is zero, and hence you are indeed >weightless. But you must be accelerated, otherwise you would go in a straight line! >p.s. Does someone remember the details of the "thought" experiment > involving being in a windowless elevator, and trying to determine > whether you are accelerating or just plain heavy ? Well, the result of that thought experiment is called the General Theory of Relativity which starts by saying (speaking loosely) that you can't tell a difference because both possibilities amount to the same thing. Anyway, I'm glad you brought up the elevator (don't say a word, Henry). If you're in a falling elevator you're weightless too, aren't you? But the gravitational field is still the same, isn't it? Let me offer a hint: We need a better definition of weight, and possibly a better notion of acceleration, to solve the problem. But no deep dark physics is needed, just careful thought. -- D Gary Grady Duke U Comp Center, Durham, NC 27706 (919) 684-3695 USENET: {seismo,decvax,ihnp4,akgua,etc.}!mcnc!ecsvax!dgary