Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: Notesfiles; site hpcnoe.UUCP Path: utzoo!linus!decvax!genrad!mit-eddie!think!harvard!seismo!hao!hplabs!hpfcdc!hpfcla!hpcnoe!jeff From: jeff@hpcnoe.UUCP Newsgroups: net.games.board Subject: Re: Dice "Odds" Message-ID: <37800027@hpcnoe.UUCP> Date: Sat, 14-Dec-85 20:59:00 EST Article-I.D.: hpcnoe.37800027 Posted: Sat Dec 14 20:59:00 1985 Date-Received: Tue, 14-Jan-86 07:48:12 EST References: <309@tekigm2.UUCP> Organization: 14 Dec 85 18:59:00 MST Lines: 28 > Given that you use two dice in a game and that you are trying to figure > the odds of getting a particular combination: do you use the combinations > or the permutations to determine the odds? > > Permutations Combinations > Number Ways Number Ways > 2 1 2 1 > 3 2 3 1 > 4 3 4 2 > 5 4 5 2 > 6 5 6 3 > 7 6 7 3 > 8 5 8 3 > 9 4 9 2 > 10 3 10 2 > 11 2 11 1 > 12 1 12 1 > --- --- > 36 21 > Actually, in the strict mathmatical sense, this is neither a "permutations" problem nor a "combinations" problem--factorials are not involved. The correct answer is the left column e.g. there is two ways of throwing a three (1 2) and (2 1), the two are equally likely because the dice have no knowledge of what the other has thrown. -- Jeff Wu