Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site molihp.UUCP Path: utzoo!utcsri!ubc-vision!molihp!martinl From: martinl@molihp.UUCP (Martin M Lacey) Newsgroups: net.puzzle Subject: Re: Explorer paradox * SEMI-SPOILER * Message-ID: <128@molihp.UUCP> Date: Tue, 7-Jan-86 16:03:11 EST Article-I.D.: molihp.128 Posted: Tue Jan 7 16:03:11 1986 Date-Received: Wed, 8-Jan-86 10:03:07 EST References: <2667@sunybcs.UUCP> <1478@sphinx.UChicago.UUCP> <1011@ecsvax.UUCP> Reply-To: martinl@HP-UX.UUCP (Martin M Lacey) Organization: Moli Energy, Vancouver, B.C., CANADA Lines: 49 Summary: In article <1011@ecsvax.UUCP> hes@ecsvax.UUCP (Henry Schaffer) writes: >> >> > From: colonel@sunybcs.UUCP (Col. G. L. Sicherman) >> > Message-ID: <2667@sunybcs.UUCP> >> > Here's a new one: a practical joker tampered with the Great Explorer's >> > gyrocompass, so it points 45 degrees off. The Great Explorer thinks >> > he's going due north on his way to the North Pole, but he's really going >> > due northwest! >> > >> > Will he reach the North Pole anyway? (Geographers keep out of this one!) >> My own thoughts about this are as follows. If this explorer is following the compass at all, he should eventually arrive at the north pole after a number of spirals toward it. My thinking goes like this; if this compass points anything less that 90 degress away from north, he will eventually find north by its vector quality. That is to say, if you subtract the e-w direction component away from the vector, you are left with the north component of the vector. This northern component may be small, but it exists; so the explorer shall eventually get there. The greater the e-w component as compare to the norther component of the vector (ie. closer to 90 degrees from north) the longer the distance (number of spirals) before the explorer gets to the North Pole. It can be easily visualized if you think as the world as flat and repeating, and the north pole is a straight line on the top. This way the problem can be solved using simple geometry. Eg. Earth1 Earth2 Earth3 Earth4 ... ---------------------------------...-------NORTH POLE LINE-- | | | | * |... ^ | | | * |... | | | | * | |... | | | * | | |... X | * | | |... | | * | | | |... | _________________________________...____________+_______ <------------Y------------> where * is the explorer, and each one the earths represents one revolution of the planet. The less the angle at Y start, the more earths the explorer has to pass through, hence the distance. Anyone care to comment....It seemed logical to me; but I may be missing something fundamental - unlikely though :-). Martin the Magician.