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From: rokicki@Navajo.ARPA
Newsgroups: net.micro.amiga
Subject: Amiga memory management
Message-ID: <301@Navajo.ARPA>
Date: Fri, 24-Jan-86 23:36:51 EST
Article-I.D.: Navajo.301
Posted: Fri Jan 24 23:36:51 1986
Date-Received: Sun, 26-Jan-86 05:13:26 EST
Distribution: net
Organization: Stanford University
Lines: 42

*** REPLACE THIS LINE WITH YOUR BROTHER ***

	Here is a simple C routine I threw together which should
determine the amount of memory accessible by C (at least a rough
approximation.)  When I run it, it dies; but it consists solely of
calls to AllocMem!  Any hints out there?

/*
 *   This routine finds out how much memory is available to a C program
 *   by simply allocating successively larger pieces until it fails,
 *   and then successively smaller pieces, adding them up as it goes.
 *   This will only work if the memory is not terribly fragmented, but
 *   if it is, it might not be that useful, eh?
 */
char *AllocMem() ;
main ()
{
   char *p ;
   int i, j ;

   j = 0 ;
   for (i=4; 1; i<<=1) {
      p = (char *)AllocMem(i, 0) ;
      if (p == 0)
         break ;
      else {
         j += i ;
         printf("%d %d\n", i, j) ;
      }
   }
   for (; i>=4; i>>=1) {
      p = (char *)AllocMem(i, 0) ;
      if (p !=0) {
         j += i ;
         printf("%d %d\n", i, j) ;
      }
   }
}

It crashes the machine (at least it crashes my 512K machine).  Help!
I want my program to take advantage of the memory available, but if
it can't even figure how much exists, how can it?   -tom