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From: neil@amiga.UUCP (Neil Katin)
Newsgroups: net.micro.amiga
Subject: Re: Amiga memory management
Message-ID: <621@amiga.amiga.UUCP>
Date: Wed, 29-Jan-86 17:09:57 EST
Article-I.D.: amiga.621
Posted: Wed Jan 29 17:09:57 1986
Date-Received: Sat, 1-Feb-86 00:43:26 EST
References: <301@Navajo.ARPA>
Reply-To: neil@rocky.UUCP (Neil Katin)
Distribution: net
Organization: Commodore-Amiga Inc., 983 University Ave #D, Los Gatos CA 95030
Lines: 17

In article <301@Navajo.ARPA> rokicki@Navajo.ARPA writes:
>	Here is a simple C routine I threw together which should
>determine the amount of memory accessible by C (at least a rough
>approximation.)  When I run it, it dies; but it consists solely of
>calls to AllocMem!  Any hints out there?

Tom then goes on with a program that allocates all of memory.

A much more reasonable way is to use the AvailMem() call.

    AvailMem(0) will return the total number of free bytes in the memory pool

    AvailMem( MEMF_LARGEST ) will return the largest contiguous chunk
	of memory (e.g. the largest AllocMem that will succeed ).

Neil Katin
Commodore-Amiga, Inc.