Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site mmintl.UUCP Path: utzoo!watmath!clyde!burl!ulysses!bellcore!decvax!linus!philabs!pwa-b!mmintl!franka From: franka@mmintl.UUCP (Frank Adams) Newsgroups: net.ai,net.philosophy Subject: Re: A halting problem: a meaty response Message-ID: <1139@mmintl.UUCP> Date: Mon, 3-Feb-86 22:28:59 EST Article-I.D.: mmintl.1139 Posted: Mon Feb 3 22:28:59 1986 Date-Received: Sun, 9-Feb-86 05:24:20 EST References: <2175@aecom.UUCP> <14551@rochester.UUCP> <3978@kestrel.ARPA> <1070@mmintl.UUCP> <4374@kestrel.ARPA> Reply-To: franka@mmintl.UUCP (Frank Adams) Distribution: net Organization: Multimate International, E. Hartford, CT Lines: 37 Xref: watmath net.ai:3262 net.philosophy:4108 In article <4374@kestrel.ARPA> ladkin@kestrel.ARPA writes: >(wiener) >> >There are problems now known which are believed forever insoluble. >> >(adams) >> There does not seem to be any way to know that a problem >> is definitely insoluble (as distinct from undecidable in a formal system). > >There are theorems such as Kruskal's, the Paris-Harrington >version of the Ramsey Theorem, and Friedman's various principles >that are provable stronger than the generally acceptable >principles of arithmetic, and recursive set theory. They are >arguably consistent, since there are `proofs' of them. >These proofs must depend upon stronger principles than all >mathematicians are willing to accept (e.g. intuitionists). >If you believe these proofs, you will nevertheless be >unable to persuade those who are sceptical of their validity, >and furthermore, there is a proof of this fact. > >This point is even valid for Peano Arithmetic. >If you believe that Peano Arithmetic is consistent, as I do, >then there is a proof that proving the consistency of P.A. >from elementary principles is an insoluble problem. >This is different from deciding the >consistency of P.A. If you believe Gentzen's proof, as I do, >then the consistency is already decided. But if you do *not* accept the postulate, that means you are in real doubt about it. That, in turn, means you don't know whether or not it is undecidable. Because if Peano Arithmetic is not consistent, then there actually exists a counterexample, which can be demonstrated. You can, perhaps, know that someone else's problem is unsolvable *by them*, but you cannot know the same for yourself (for this class of problems, at least). Frank Adams ihpn4!philabs!pwa-b!mmintl!franka Multimate International 52 Oakland Ave North E. Hartford, CT 06108