Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/5/84; site ism780c.UUCP Path: utzoo!watmath!clyde!burl!ulysses!gamma!epsilon!zeta!sabre!petrus!bellcore!decvax!ittatc!dcdwest!sdcsvax!sdcrdcf!ism780c!tim From: tim@ism780c.UUCP (Tim Smith) Newsgroups: net.physics Subject: Re: electrons Message-ID: <339@ism780c.UUCP> Date: Tue, 28-Jan-86 15:33:49 EST Article-I.D.: ism780c.339 Posted: Tue Jan 28 15:33:49 1986 Date-Received: Thu, 30-Jan-86 06:46:47 EST References: <1165@homxb.UUCP> <557@well.UUCP> Reply-To: tim@ism780c.UUCP (Tim Smith) Organization: Interactive Systems Corp., Santa Monica, CA Lines: 9 > Last, multiply by the atomic number of copper, to give the number >of protons in the sphere in question. Assuming no net charge, this >will also be the number of electrons in the sphere. > If the sphere is negatively charged, you still get the right answer, because copper is a conducter, so the extra electrons end up on the surface instead of _in_ the sphere. -- Tim Smith sdcrdcf!ism780c!tim || ima!ism780!tim || ihnp4!cithep!tim