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From: jsdy@hadron.UUCP (Joseph S. D. Yao)
Newsgroups: net.unix,net.unix-wizards,net.wanted
Subject: Re: Need unix command file HELP!
Message-ID: <259@hadron.UUCP>
Date: Tue, 11-Feb-86 00:18:39 EST
Article-I.D.: hadron.259
Posted: Tue Feb 11 00:18:39 1986
Date-Received: Thu, 13-Feb-86 17:42:04 EST
References: <245@aero.ARPA> <587@smeagol.UUCP>
Reply-To: jsdy@hadron.UUCP (Joseph S. D. Yao)
Organization: Hadron, Inc., Fairfax, VA
Lines: 44
Xref: linus net.unix:6533 net.unix-wizards:13930 net.wanted:7470
Summary: grep won't always print file name!

All the folk who are responding that the way to get the file names
of files containing a particular string are kind of forgetting that
the grep family does  n o t  automatically print out file names.
This:

>find / -exec fgrep this-is-the-string '{}' \;

will give a file full of lines containing this-is-the-string.  Try:

find / -exec grep this-is-the-string '{}' /dev/null \;

**OR** (quicker) :

find / -type d -a -exec ksh findstr "this-is-the-string" {} \;

findstr:
#!/bin/ksh
# or /bin/sh

str="$1"
dir="$2"
file=""
text=""

if [ ! -d "$dir" ]; then exit 1; fi

cd "$dir"

for file in *; do
	if [ ! -f "$file" ]; then continue; fi
	text=`file "$file" | grep text`
	if [ "" = "$text" ]; then continue; fi
	# if you want the complete text:
	# grep "$str" "$dir/$file" /dev/null
	# otherwise
	text=`grep "str" "$file" | line`
	if [ "" != "$text" ]; then
		echo "$dir/$file"
	fi
done
exit 0
-- 

	Joe Yao		hadron!jsdy@seismo.{CSS.GOV,ARPA,UUCP}