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From: hucka@utah-cs.UUCP (Michael Hucka)
Newsgroups: net.lang.lisp
Subject: Re: programming trick
Message-ID: <3699@utah-cs.UUCP>
Date: Sat, 1-Mar-86 12:26:00 EST
Article-I.D.: utah-cs.3699
Posted: Sat Mar  1 12:26:00 1986
Date-Received: Sun, 2-Mar-86 19:14:31 EST
References: <136@cui.UUCP>
Reply-To: hucka@utah-cs.UUCP (Michael Hucka)
Organization: VCIS Research Group
Lines: 29

In article <136@cui.UUCP> manuel@cui.UUCP (James Stewart) writes:
> I've often run into the problem of wanting to apply a function to
> every element of a list, but been stuck because the function takes
> more than one argument.  As a simple example:
>
>  (defun F (x y) 
>    (+ x y))
>
>  (setq L '(2 4 6 8))
>
> How do we add 10 to each element of L?
>
> [examples and more discussion . . .]

As an alternative, you could also do the following (assumine "L" and "F"
are already defined):

   (let ((arg2 10))
     (mapcar #'(lambda (arg1) (F arg1 arg2)) L))

Whether this works correctly may depend on the scoping aspects of the dialect
of Lisp you are using.  I believe this code is fairly transparent, though
others may disagree with me . . . .

							Mike
-- 
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::::::  Mike Hucka {ihnp4 decvax}!utah-cs!hucka, hucka@utah-cs.ARPA    ::::
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