Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84 exptools; site ihnet.UUCP Path: utzoo!watmath!clyde!cbosgd!ihnp4!ihnet!eklhad From: eklhad@ihnet.UUCP (K. A. Dahlke) Newsgroups: net.math Subject: Groups, Alternative Definitions? Message-ID: <370@ihnet.UUCP> Date: Tue, 4-Mar-86 09:37:40 EST Article-I.D.: ihnet.370 Posted: Tue Mar 4 09:37:40 1986 Date-Received: Wed, 5-Mar-86 05:29:15 EST Distribution: net Organization: AT&T Bell Laboratories Lines: 46 If we modify the definition of a group slightly, do new groups arise? I have never had a group theory course, so if this is all standard established knowledge, forgive me. I thought the question was interesting. Review: A group is a set of elements S and an operator '*', possessing the following properties: The binary operator '*' is a well defined function, closed in S. The operator '*' is associative. There is a unique identity element E, such that X*E = E*X = X for every X. Every X has a unique inverse Y, such that X*Y = Y*X = E. Consider the identity and inverse properties of a group, as outlined above. Suppose the order of the operands is significant. Example: every X has a unique inverse Y, such that X*Y = E. No constraints placed upon Y*X. There are four possible "weakened" definitions: identity inverse 1. X*E = X X*Y = E 2. E*X = X X*Y = E 3. E*X = X Y*X = E 4. X*E = X Y*X = E If I have not made any serious blunders, each weaker definition implies the other three, resurrecting the original concept. By symmetry, definitions 1 and 3 are equivalent, producing reflected theorems. Similarly, 2 and 4 are equivalent. Therefore, we consider only 1 and 2. Suppose we adopt definition 1. Every X has an inverse Y, and this Y must have an inverse Z. Multiply the equation X*Y = E by Y on the left and Z on the right. After invoking associativity and identity properties, we have Y*X*(Y*Z) = Y*Z. Since Z is the inverse of Y, this reduces to Y*X = E. Thus, if Y is the inverse of X, then X is the inverse of Y. To prove E*X = X, begin with Y*E = Y, where Y is the inverse of X. Multiply by X on the right and on the left, and reduce the equation to E*X = X. Thus, definition 1 implies all the original axioms. Starting with definition 2 is more challenging. I will leave this as an exercise for the interested. -- When the sky becomes uranious, we will all go simultaneous. Karl Dahlke ihnp4!ihnet!eklhad