Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site hropus.UUCP Path: utzoo!watmath!clyde!cbosgd!ihnp4!houxm!hropus!jin From: jin@hropus.UUCP (Jear Bear) Newsgroups: net.med Subject: Re: exercise? Message-ID: <327@hropus.UUCP> Date: Thu, 6-Mar-86 12:49:42 EST Article-I.D.: hropus.327 Posted: Thu Mar 6 12:49:42 1986 Date-Received: Fri, 7-Mar-86 07:35:53 EST References: <5079@alice.uUCp> Organization: Bell Labs, Holmdel, NJ Lines: 10 To answer you literally: No input is necessary to output that amount of energy, the body will usually have enough stored energy. To calculate kilocalories (the nutritionist's type) multiply watt-hours by 0.8605 So your example (if my memory serves me correctly) is .8605*(150.*15./60.) or 32.27 (rounded) kcals. -- Jerry Natowitz ihnp4!houxm!hropus!jin The Master Baker