Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/17/84; site mhuxm.UUCP Path: utzoo!linus!decvax!bellcore!ulysses!mhuxr!mhuxn!mhuxm!abeles From: abeles@mhuxm.UUCP (J. Abeles (Bellcore, Murray Hill, NJ)) Newsgroups: net.physics Subject: Limitations on High Electric Fields Message-ID: <523@mhuxm.UUCP> Date: Wed, 19-Feb-86 00:26:06 EST Article-I.D.: mhuxm.523 Posted: Wed Feb 19 00:26:06 1986 Date-Received: Thu, 20-Feb-86 00:06:22 EST Organization: AT&T Bell Laboratories, Murray Hill Lines: 25 Question: I am aware that the breakdown electric field in air is typically quoted as 10kV/cm. In various dielectrics the breakdown can be higher--400kV/cm in insulating GaAs is a typical figure for that material. My question--what is the breakdown field in a vacuum? What influences it? In extreme high voltages, pair production may occur. From a negatively charged electrode, cold emission can occur sending electrons into the vacuum. Another possible effect is due to the lack of a perfect vacuum, and I recall that in geiger counters a low pressure is purposely selected to get large currents because of special properties in the 1 torr or so range. Do the residual gases always dominate the breakdown process in practically attainable vacua? Or possibly can UHV systems achieve much greater dielectric strengths? Does anyone have a practical answer to these questions, or better yet, a good reference? --Joe Abeles