Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site ttidcb.UUCP Path: utzoo!watmath!clyde!burl!ulysses!bellcore!decvax!linus!philabs!ttidca!ttidcb!pumphrey From: pumphrey@ttidcb.UUCP (Larry Pumphrey) Newsgroups: net.math Subject: Re: I need an A in linear algebra! Help! Message-ID: <714@ttidcb.UUCP> Date: Wed, 12-Mar-86 11:44:25 EST Article-I.D.: ttidcb.714 Posted: Wed Mar 12 11:44:25 1986 Date-Received: Sat, 15-Mar-86 20:13:08 EST References: <967@nmtvax.UUCP> Organization: TTI, Santa Monica, CA. Lines: 36 I think you need to supply more information as there appear to be counter-examples as the problem is stated. The following points should be clarified. 1. Over what field do the elements a of the matrices M ij i range (and hence k in the companion matrix A)? i.e., the rationals, reals, complexes? 2. Any restrictions on the value of k? 3. Can any of the M be the identity matrix? i Counter-example: ---------------- If there are no restrictions on the value of k in the A matrix then let k=1 and A becomes the identity matrix. Consider the 8 3X3 matrices, M as follows: i [1 0 0] [1 0 0] [1 0 0] [1 0 0] M = [0 1 0] M = [0 1 0] M = [0 -1 0] M = [0 -1 0] 1 [0 0 1] 2 [0 0 -1] 3 [0 0 1] 4 [0 0 -1] [-1 0 0] [-1 0 0] [-1 0 0] [-1 0 0] M = [ 0 1 0] M = [ 0 1 0] M = [ 0 -1 0] M = [ 0 -1 0] 5 [ 0 0 1] 6 [ 0 0 -1] 7 [ 0 0 1] 8 [ 0 0 -1] Note that all 8 matrices are distinct, each M squared is the i identity and their product is A = I. Also note that M = I. 1 It's an interesting problem, but something appears to be missing. - Larry