Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/17/84; site mhuxh.UUCP Path: utzoo!watmath!clyde!burl!ulysses!mhuxr!mhuxn!mhuxm!mhuxf!mhuxi!mhuxh!twb From: twb@mhuxh.UUCP (twb) Newsgroups: net.puzzle Subject: Re: Mixing Liquids (SPOILER!!) Message-ID: <342@mhuxh.UUCP> Date: Fri, 21-Mar-86 09:19:48 EST Article-I.D.: mhuxh.342 Posted: Fri Mar 21 09:19:48 1986 Date-Received: Sat, 22-Mar-86 22:33:43 EST References: <1907@trwrba.UUCP> <184@winston.UUCP> <2955@sunybcs.UUCP> Organization: AT&T Bell Laboratories, Murray Hill Lines: 22 > Puzzle: > > Take a half a cup of tea, and a half a cup of coffee. > Take one tablespoon of the tea and mix it in with the coffee. > Take one tablespoon of the mixture and mix it back in with the tea. > > The question is, which of the two cups (if either) contains more of > its original contents, and WHY. > > Remember, I'm looking for simple, elegant solutions here.... > 1. T represents Tea, C represents Coffee 2. Start with 8 tbl(=1/2cup) of each. 8T 8C 3. Coffee get 1T 7T 8C+1T 4. 1 tbl of the C mixture is 1/9T+8/9C 5. Put that into the T cup 7 1/9T+ 8/9C 7 1/9C+ 8/9T 6. Each cup has 7 1/9 tbl of the original contents and 8/9 tbl of the other liquid. QED Tom.