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From: dietz%slb-doll.csnet@CSNET-RELAY.ARPA
Newsgroups: net.lang.c
Subject: Re: Pointers to arrays in C
Message-ID: <2389@brl-smoke.ARPA>
Date: Fri, 4-Apr-86 23:03:37 EST
Article-I.D.: brl-smok.2389
Posted: Fri Apr  4 23:03:37 1986
Date-Received: Wed, 9-Apr-86 07:52:20 EST
Sender: news@brl-smoke.ARPA
Lines: 26

>>	    int (*x)[10];
>
>That is not a pointer to an array.  It is an array of pointers to ints.
>	George Tomasevich, ihnp4!twitch!grt
>	AT&T Bell Laboratories, Holmdel, NJ

It *is* a pointer to an array.  Try running this program:

    main()
    {
	char (*x)[10];
	printf("%d\n%d\n%d\n", sizeof(*x), sizeof(x), sizeof((*x)[2]));
    }

It prints (on a VAX running ULTRIX):

10
4
1

So, *x is an object of size 10 (the array), x is an object of size 4 (a
pointer), and (*x)[2] is a single byte (a char).  C's strange type
syntax strikes again.

Paul Dietz
dietz@slb-doll.csnet